[Frage] [PythonParts] GetParentElement

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  • Pythonpart
  • PARENT
cmaignan35
cmaignan35
25.08.2023 - 08:49 *

Hi,

I place a PythonPart in a room.

I'd like to retrieve the room's name with GetParentElement (I already created the link between the 2).

I tried :

pythonpart = ElementAdapter.BaseElementAdapter.FromNOIGUID(self.modify_uuid_list[0], self.coord_input.GetInputViewDocument())
local = ElementAdapter.BaseElementAdapterParentElementService.GetParentElement(pythonpart)

but it doesn't work

What is the correct syntax ?

PS I want to get the @507@ attribute of the room as in the annotation

Best Regards

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bmarciniec
bmarciniec
31.08.2023 - 14:35 *

Well, Colliding is as far as I know not capable of checking the intersection between two polyhedrons. For two polyhedrons use Intersect.

You can also use Intersecting for checking Polyhedrons with BRep. I never tested it, but I guess it might be more performant, as it only checks if the two are intersecting, without actually performing the boolean operation of intersection.

11 - 14 (14)
cmaignan35
cmaignan35
30.08.2023 - 06:58

Hi,

What if I select by script all the rooms to create for each a bounding box.

I could check with IsContaining if my object is in the room ?

Best

bmarciniec
bmarciniec
31.08.2023 - 06:49 *

Hi,

I am not sure, which function to use to get the geometry of a room correctly, but it must be either GetModelGeometry or GetPureArchitectureElementGeometry(). You should get a Polyhedron3D as a result. You can then either try with IsContaining method of a bounding box, but your room will not always have a geometry of a box in the ground view. The alternative is to use the DeterminePosition class. It is capable of determining a position of a point in relation to a polyhedron (outside, inside, onElement). In this case, you have to choose a relevant point (or points) of the element you want to determine the position of (the doors).
Alternatively you can perform a subtraction: of the door is fully in the room, subtracting the room polyhedron from the door will result in a polyhedron type of tInvalid.
With the version 2023-1-5 we will publish an article in our manual about the usage of DeterminePosition and Boolean operations together with some examples in the PythonPartExamples library.

Best regards

cmaignan35
cmaignan35
31.08.2023 - 07:05

Hi,

Thanks for these alternative proposals.

With a polyhedron there is also the Colliding function.... I will test it.

Looking forward to seeing these new examples

Best

bmarciniec
bmarciniec
31.08.2023 - 14:35 * [Hilfreichste Antwort]

Well, Colliding is as far as I know not capable of checking the intersection between two polyhedrons. For two polyhedrons use Intersect.

You can also use Intersecting for checking Polyhedrons with BRep. I never tested it, but I guess it might be more performant, as it only checks if the two are intersecting, without actually performing the boolean operation of intersection.

11 - 14 (14)